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30 October, 12:16

How much force is needed to stretch a spring 1.2 m if the spring constant is 8.5 n/m? 7.1 n 7.3 n 9.7 n 10.2 n

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  1. 30 October, 12:49
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    Based on Hooke's Law, the force applied on the spring is equal to the product of the spring constant and the length sagged by the spring.

    F = k x

    where k is the spring constant

    x is the length

    Given from the problem is k = 8.5 n/m; and x = 1.2 m

    So,

    F = 8.5 N/m * 1.2 m

    F = 10.2 N
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