A 2000 kg car experiences a constant braking

force of 10,000 N, and comes to be a stop in 6

sec.

What would be the distance traveled by the

car in coming to rest?

Solving for acceleration:

F = ma

10000 = 2000*a

a = 5 m/s^2

Solving for velocity:

Vf = Vi + a (t)

0 = Vi - (5) (6)

Vi = 30 m/s

Solving for displacement or distance:

S = Vi*t - 1/2 * a * t^2

S = 30 (6) - 1/2 (5) (6) ^2

S = 90m

The car would have traveled 90m before coming to rest.