Two oppositely charged parallel metal plates,

1.00 centimeter apart, exert a force with a

magnitude of 3.60 * 10^-15 newton on an electron

placed between the plates. Calculate the

magnitude of the electric field strength between

the plates. [Show all work, including the

equation and substitution with units.]

Question

Physics

Ward

21 December, 05:53

Two oppositely charged parallel metal plates,

1.00 centimeter apart, exert a force with a

magnitude of 3.60 * 10^-15 newton on an electron

placed between the plates. Calculate the

magnitude of the electric field strength between

the plates. [Show all work, including the

equation and substitution with units.]

+4

Answers (1)

Know the Answer?

Avah Reynolds · Answer 1

Electric field strength = Force/Charge

E = (3.6*10^-15) / (1.6*10^-19) = 2.25*10^4 N/c

1.6*10^-19 being the elementary charge that is a fundamental constant, and is the charge on an electron.