A cannon, elevated at 40 is fired at a wall 300 m away on level ground, as shown in the figure below. The initial speed of the cannonball is 89

The given data are: initial angle of elevation of 40 degrees and the distance from the wall of 300 m. The initial speed is 89 m/s. If the problem asks for the time to reach the 300 m span, we use the equation x = v t cos theta. Substituting, we get 300 = 89*t*cos 40. t is equal to 4.40 seconds.