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18 July, 20:25

A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that time, at which rate is the diver accelerating?

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Answers (2)
  1. 18 July, 23:29
    0
    Your answer would be 9.8
  2. 18 July, 23:55
    0
    Acceleration = (change in speed) / (time for the change)

    = (49 m/s) / (5 seconds)

    = (49 / 5) m/s / s

    = 9.8 m/s²
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