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15 February, 23:42

How many calories of heat must you remove if you want to lower the temperature of 350 g of steel from 18.0 °c to 12.0 °c? the specific heat of steel is 0.11 cal/g °

c.?

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  1. 16 February, 03:06
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    Heat to be removed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

    Heat = mC (T2-T1)

    Heat = 350 (0.11) (12.0 - 18.0)

    Heat = - 231 cal
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