A daredevil is shot out of a cannon at 45.0° above horizontal with an initial speed of 25.0 m/s. a net is positioned a horizontal distance of 50.0 m from the cannon. at what height above the cannon should the net be placed in order to catch the daredevil?

Question

Physics

Sammy Whitehead

7 January, 16:08

A daredevil is shot out of a cannon at 45.0° above horizontal with an initial speed of 25.0 m/s. a net is positioned a horizontal distance of 50.0 m from the cannon. at what height above the cannon should the net be placed in order to catch the daredevil?

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Answers (1)

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Jovan · Answer 1

S = vcos (x) t

50 = 25cos (45) t

cos (45) t = 2

t = 2/cos (45) = 2sqrt (2)

h = vsin (x) t + gt^2/2

h = 25sin (45) * 2sqrt (2) - 4.9*8

h = 10.8 metres