What is the angular speed of (a) the second hand, (b) the minute hand, and (c) the hour hand of a smoothly running analog watch? answer in radians per second?

A) We know the formula of the angular speed is ω = 2π / TWhere T is the time period. When second hand completes one revolution then the time taken is 60s. So T = 60sThen the angular speed of the second hand is ω = 2π / (60s) = 0.1047 rad/sb) When the minute hand completes one revolution the time taken is T = 1 hr = 3600sThen the angular speed of the minute hand is ω = (2π) / (3600s) = 0.001745 rad/sc) When the hour hand completes one revolution then the timeperiod is T = 12hrs = (12) (3600) sThen the angular speed of the hour hand is ω = (2π) / [ (12) (3600) s] = 1.45444 x 10^-4 rad/s