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11 March, 20:33

At what distance above earth would a satellite have a period of 125 min?

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  1. 11 March, 20:53
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    Rw^2 = GmM/r^2

    Leads to

    w^2 r^3 = GM

    (2pi / T) ^2 r^3 = GM

    4pi^2 r^3 = GM T^2

    r^3 = GM T^2 / 4pi^2

    Work out r^3 then r.

    T = 125 min = 125 (60) = 7500 s

    R = 6.38E6 m

    m = 5.97E24 kg

    G = 6.673E-11

    r = 8279791.78 m

    Since r = radius R of Earth + height above urface, h

    h = r - R = 8279791.78 - 6.38E6 = 1899791.78 m

    h = 1899.79178 Km
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