A ball is thrown 24 m/s into the air. How high does it go?

It goes 24 m/s in the air

Vi = 24

Vf = 0

A = 9.81 m/s ^2

D = ? m

Vf^2 = Vi^2 + 2ad

0 = (24) ^2 + 2 (-9.81) (d)

0 = 576 + (-19.62d)

-576 = - 19.62d

-576/-19.62 = - 19.62d/-19.62

D = 29.35 m.

I believe this would be the solution.