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9 January, 06:07

How much work is needed for a 77-kg runner to accelerate from rest to 11.5 m/s?

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  1. 9 January, 07:01
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    Work done is change in kinetic energy. That is work done = K. E (final) - K. E (initial) K. E = (mass*velocity*velocity) / 2 Given the runner accelerates from rest hence initial kinetic energy is 0 since initial velocity is 0. Final kinetic energy = (77kg*11.5m/s*11.5m/s) / 2 = 5091.625 joules Hence the work done by the 77kg runner to accelerate from rest to 11.5 m/s is 5.0916 Kilo joules.
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