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6 October, 11:25

If the distance between two objects is decreased to one fourth of the original distance how will the decrease change the force of attraction between the objects

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  1. 6 October, 12:04
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    F = GMm/r²

    The relationship between F and r is an inverse one. So if the distance r decreases, to 1/4 the original distance:

    Let F α 1/r²

    F = k/r²

    or F₂ / F₁ = (r₁ / r₂) ²

    If r is decreased to 1/4,

    F₂ / F₁ = (r₁ / r₂) ²

    F₂ / F₁ = (r₁ / (1/4r₁)) ²

    F₂ / F₁ = (4) ²

    F₂ / F₁ = 16

    F₂ = 16F ₁

    The new force of attraction would be 16 times the former value.
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