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23 April, 16:52

The force of attraction between two oppositely charged pith balls is 5.3 * 10-6 newtons. If the charge on the two objects is 6.7 * 10-9 coulombs, what is the distance between the two charges? (k = 9.0 * 109 newton·meter2/coulombs2)

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  1. 23 April, 19:40
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    6.7x10^-1 Meters

    Just run it through the formula.
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