A young's interference experiment is performed with blue-green laser light. the separation between the slits is 0.500 mm, and the screen is located 3.14 m from the slits. the first bright fringe is located 3.32 mm from the center of the interference pattern. what is the wavelength of the laser light?

Question

Physics

Paxton Hardy

1 October, 19:35

A young's interference experiment is performed with blue-green laser light. the separation between the slits is 0.500 mm, and the screen is located 3.14 m from the slits. the first bright fringe is located 3.32 mm from the center of the interference pattern. what is the wavelength of the laser light?

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Giana Mcdonald · Answer 1

Use the relation dsin (θ) = mλ

Your angle is given by θ=tan⁻¹ (3.32e-3/3.14) = 0.06058 degrees

λ = dsin (θ) / m = (0.5e-3) (0.001057) / 1 (use 1 in denominator since its the first order maximum)

λ = 5.2866e-7 Or λ = 528.66nm