A 1451 kg car is traveling at 48.0 km/h.

How much kinetic energy does it possess? K. E. =

1.67 x 105 J

9.65 x 105 J

1.28 x 105 J

3.48 x 105 J

Would be a. since KE = 1/2 m*v^2

KE = (1/2) · (1,451 kg) · (48 km/hr) ² · (1000 m/km) ² · (1 hr/3,600 sec) ²

= (725.5) · (48 · 1000 · 1 / 3,600) ² (kg) · (km·m·hr / hr·km·sec) ²

= (725.5) · (40/3) ² · (kg·m² / sec²)

= 128,978 joules (rounded)