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2 September, 19:23

A kicker kicks a football toward the opponent's goal line during a game. The ball begins its flight with an initial velocity of 70 feet per second when it is kicked at a height of 2 feet by the kicker. To the nearest foot, what maximum height will the ball reach?

You may use the function:

h (t) = - 16t^2+70t+2

A. The answer cannot be determined.

B. 79 feet

C. 981 feet

D. 129 feet ... ?

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Answers (2)
  1. 2 September, 20:49
    0
    16t^2 + 70t + 2 - b/2a gives maximum height - 70/-32 f (70/32) = 79 B. 79 Feet
  2. 2 September, 21:27
    0
    h (t) = - 16t^2 + 70t + 2

    h' (t) = - 32t + 70

    0 = - 32t + 70

    32t = 70

    t = 70/32

    t = 35/16

    Using either method, t = 35/16.

    h (35/16) = - 16 (35/16) ^2 + 70 (35/16) + 2

    h (35/16) = - 16 (1225/256) + 2450/16 + 2

    h (35/16) = - 1225/16 + 2450/16 + 32/16

    h (35/16) = 1257/16

    So the maximum height is 1257/16 feet, which is 78.5625 feet.

    To the nearest foot, that's 79 feet.
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