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19 June, 09:53

A piano tuner stretches a steel piano wire with a tension of 765 n. the steel wire has a length of 0.900 m and a mass of 6.75 g. part a what is the frequency f1 of the string's fundamental mode of vibration?

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  1. 19 June, 10:08
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    To solve for this we need to find µ

    So the formula is µ = m/L =.00675/0.900 = 0.0075 kg/m

    Speed of wave u = √[T/µ] = √[765/µ] = 319.4 m/s

    f1 is now computed by (1/2L) * u

    So plugging in our values, (1/2*.9000m) * 0.0075 kg/m = 177.4 Hz
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