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18 January, 19:50

A 20000 kg railroad car is rolling at 1.00 m/s when a 1000 kg load of gravel is suddenly dropped in. part a what is the car's speed just after the gravel is loaded?

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  1. 18 January, 23:22
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    Using conservation of energy and momentum we get m1*v1 = (m1+m2) * v2 so rearranging for v2 and plugging the given values in we get:

    (200000kg*1.00m/s) / (21000kg) =.952m/s
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