How much heat is absorbed by a 71g iron skillet when its temperature rises from 11oC to 29oC?

The right formula to use for this calculation is the heat capacity formula,

Heat absorbed, Q = MCT, Where

M = Mass of the substance = 71

C = Specific heat capacity for iron = 0.450 J/gc

T = Change in temperature = 29 - 11 = 18

Q = 71 * 0.450 * 18 = 575.10

The amount of heat absorbed by the iron skillet is 575 J.