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13 June, 20:57

A tow truck applies a 848 N to a car at a 32.5°angle, and pulls the car 48.7 m in 18.3s. How much power was the truck using to tow the car?

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  1. 13 June, 21:40
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    Power is the ratio of work done and the time taken to do the work.

    So,

    Power = Work Done / Time

    Work done is the dot product of force and distance.

    So,

    Work done = F. d = Fdcos (Ф)

    where Ф is the angle between force and displacement. Using the values, we get:

    Work done = 848 x 48.7 x cos (32.5) = 34830.04 Joules

    So,

    Power = 34830.04/18.3 = 1903.28 W

    Thus, truck was using 1903.28 Watts to tow the car
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