Ask Question
21 October, 11:46

If a ball is thrown straight up into the air with an initial velocity of 45 ft/s, it height in feet after t second is given by y=45t-16t2. Find the average velocity for the time period begining when t=2 and lasting. 0.1 seconds?

+2
Answers (1)
  1. 21 October, 14:51
    0
    Y = 45 t - 16 t²

    f (2 s) = 45 · 2 - 16 · 4 = 90 - 64 = 26 ft

    f (2.1 s) = 45 · 2.1 - 16 · 4.41 = 94.5 - 70.56 = 23.94 ft

    Average velocity:

    v = (23.94 - 26) / (2.1 - 2) = - 2.06 ft / 0.1 s = - 20.6 ft/s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If a ball is thrown straight up into the air with an initial velocity of 45 ft/s, it height in feet after t second is given by y=45t-16t2. ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers