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19 December, 04:14

A 2.0-kg ball rolling along a flat surface starts up a hill. If the ball reaches a height of 0.63 m, what was it's initial speed?

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  1. 19 December, 06:17
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    PE = mph

    = (2.0 kg) (9.8m/s^2) (0.63m)

    =12.35 J

    KE = 1/2mv^2

    v^2 = KE/1/2m

    =12.35 J/1/2 (2.0kg)

    v^2 = 12.35 m^2/s^2

    v = 3.51 m/s
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