A shopper in a supermarket pushes a loaded cart with a horizontal force of 13.3 Newtons. The cart has a mass of 25.1 kg and is pushed for 3.60 seconds, starting from rest?

(a) How far (in meters) will the cart move during these 3.60 seconds. (Ignore friction.)

m

(b) How far (in meters) will the cart move in the 3.60 second interval if the shopper places her 27.4-N child in the cart before she begins to push it?

m

Question

Physics

Guest

30 November, 14:14

A shopper in a supermarket pushes a loaded cart with a horizontal force of 13.3 Newtons. The cart has a mass of 25.1 kg and is pushed for 3.60 seconds, starting from rest?

(a) How far (in meters) will the cart move during these 3.60 seconds. (Ignore friction.)

m

(b) How far (in meters) will the cart move in the 3.60 second interval if the shopper places her 27.4-N child in the cart before she begins to push it?

m

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Answers (1)

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Genevieve · Answer 1

A) S (displacement) = ut+1/2at^2 a=f/m

thus s=1/2 (13.3/25.1) (3.6) ^2 ut dissapear because u=0

s=3.43m

b) the inertia has increased because the mass increases:

m (kart+child) = (245.98+27.4) / 9.8

m=27.896

s=ut+1/2at^2

s=1/2 (13.3/27.899) (3.6)

s=3.09m