The fastest pitched baseball was clocked at 46 m/s. assume that the pitcher exerted his force (assumed to be horizontal and constant) over a distance of 1.0 m, and a baseball has a mass of 145 g.

Using the Equation:

v² = vi² + 2 · a · s → Eq. 1

where,

v = final velocity

vi = initial velocity

a = acceleration

s = distance

We know that vi = 0 because the ball was at rest initially.

Therefore,

Solving Eq. 1 for acceleration,

v² = vi² + 2 · a · s

v² = 0 + 2 · a · s

v² = 2 · a · s

Rearranging for a,

a = v ²/2· s

Substituting the values,

a = 46 ²/2*1

a = 1058 m/s ²

Now applying Newton's 2nd law of motion,

F = ma

= 0.145 * 1058

F = 153.4 N