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13 January, 17:01

The fastest pitched baseball was clocked at 46 m/s. assume that the pitcher exerted his force (assumed to be horizontal and constant) over a distance of 1.0 m, and a baseball has a mass of 145 g.

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  1. 13 January, 17:25
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    Using the Equation:

    v² = vi² + 2 · a · s → Eq. 1

    where,

    v = final velocity

    vi = initial velocity

    a = acceleration

    s = distance

    We know that vi = 0 because the ball was at rest initially.

    Therefore,

    Solving Eq. 1 for acceleration,

    v² = vi² + 2 · a · s

    v² = 0 + 2 · a · s

    v² = 2 · a · s

    Rearranging for a,

    a = v ²/2· s

    Substituting the values,

    a = 46 ²/2*1

    a = 1058 m/s ²

    Now applying Newton's 2nd law of motion,

    F = ma

    = 0.145 * 1058

    F = 153.4 N
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