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16 July, 14:07

A weightlifter presses a 400 n weight 0.5 m over his head in 2 seconds, what is the power of the weight lifter

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  1. 16 July, 17:16
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    There are two ways to solve this problem. First we write the given.

    Given: Force F = 400 N; Height h = 0.5 m; Time t = 2 s

    Formula: P = W/t; but Work W = Force x distance or W = f x d

    Weight is also a Force, therefore: W = mg, solve for Mass m = ?

    m = w/g m = 400 N/9.8 m/s² m = 40.82 Kg

    P = W/t = F x d/t = mgh/t P = (40.82 Kg) (9.8 m/s²) / 2 s

    P = 100 J/s or 100 Watts
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