A quarterback throws a pass at an angle of 35◦ above the horizontal with an initial speed of 25 m/s. the receiver catches the ball 2.55 s later. determine the distance the ball was thrown.

As this is the projectile motion means the motion of object under constant acceleration, so we use all eq. of motion under constant acceleration.

Angle above horizontal=θ = 35°

Initial speed = v₁ = 25 m/s

Time of flight = t = 2.55 s

Now,

from eq. of motion

x=x₁ + (v₁*cosθ) (t) + 1/2 * a*t²

As, there is no acceleration in horizontal direction so a=0 and also initial displacement x₁=0

x = 25*cos (35) * 2.55

x=52.22 m