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Unlike the idealized voltmeter, a real voltmeter has a resistance that is not infinitely large. part a a voltmeter with resistance rv is connected across the terminals of a battery of emf e and internal resistance r. find the potential difference vmeter measured by the voltmeter.

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  1. Today, 19:30
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    The EMF of the battery includes the force to to drive across its internal resistance. the total resistance:

    R = internal resistance r + resistance connected rv

    R = r + rv

    Now find the current:

    V 1 = IR

    I = R / V1

    find the voltage at the battery terminal (which is net of internal resistance) using

    V 2 = IR

    So the voltage at the terminal is:

    V = V2 - V1

    This is the potential difference vmeter measured by the voltmeter.
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