velocity graph of a particle moving along the x-axis. Its initial position is x0 = 2m at t0 = 0. At t = 3 s, what are the particle's (a) position, (b) velocity, and (c) acceleration?

t=0 y (2) = Y0 + V0t = (2m) + (4m/s) 2sec=2+8=10m a=vf - vc / tf - tc = 0 - 4 / 4 - 2 = - 2m/s^2 so a (3) = - 2m/s2 v (3) = 2m/s2 (either directly from graph or v = vo + at = (4) + (-2) (1) = 4 - 2 = 2m/s x (3) = x (2) + v (2) deltat + 1/2 adelta t^2 = (10m) + (4m/s) (1sec) + 1/2 (-2m/s^2) (1sec) = 10m + 4m - 1m = 14m - 1m x (3) = 13m