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1 April, 12:52

If pes represents the potential energy stored in a spring in kg•m^2/s^2 and x represents the change in the springs length from its equilibrium position im m what is the unit for the spring constant k in the formula PEs=1/2kx^2

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  1. 1 April, 16:14
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    Unit for x - the change in the spring length:

    x = [ m ]

    PE s = 1/2 k x²

    [ kg m² / s² ] = 1/2 k * [ m² ] / : m²

    k = [ kg / s² ]

    Answer: The unit for spring constant k is kg / s²
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