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13 April, 12:22

If measurements if a gas are 75L and 300 full-scale and then the gas is measured a second time and found to be 50L, describe what had to happen to the pressure (if temperature remained constant).

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  1. 13 April, 13:37
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    The answer is a bit confusing, so I did some research and fount the original question. This is the complete question:

    " If measurements of a gas are 75L and 300 kilopascals and then the gas is measured a second time and found to be 50L, describe what had to happen to the pressure (if temperature remained constant). Include which law supports this observation".

    From that:

    1) dа ta:

    V1 = 75 liter

    P1 = 300 kPa

    V2 = 50 liter

    P2 = x

    T = constant.

    2) Analysis (physical law)

    Boyle's law states that the volume of a fixed amount of gas, at constant temperarature, is inversely related with the pressure.

    In mathematical form that statement becomes into this equation:

    PV = constant (at constant T)

    => P1V1 = P2V2.

    Then, the decreasing of the volumen (compression) is accompanied by an increase of the pressure.

    3) So, using Boyle's law with the data given:

    300 kPa * 75 liter = x * 50 liter

    => x = 300 kPa * 75 liter / 50 liter = 450 kPa.

    Answer: following Boyle's law, when the gas passed from 75 liter to 50 liter the pressure had to increase from 300 kPa to 450 kPa.
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