You walk with a velocity of 2 m/s north. You see a man approaching you, and from your frame of reference he has a speed of 3 m/s to the south. What is the velocity of the man from the frame of reference of a stationary observer? is it 5m to the south?

Question

Physics

Zechariah Potts

10 August, 04:09

You walk with a velocity of 2 m/s north. You see a man approaching you, and from your frame of reference he has a speed of 3 m/s to the south. What is the velocity of the man from the frame of reference of a stationary observer? is it 5m to the south?

+5

Answers (1)

Know the Answer?

Kellen Villa · Answer 1

Yep the answer is 5ms^-1

Suppose that you as A and the other man as B,

Then, V (B, A) = V (B, E) - V (A, E)

V (B, E) = V (B, A) + V (A, E)

= 3 + 2

= 5 ms^-1