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28 October, 05:51

How do you solve this If y=10^; then x=

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Answers (2)
  1. 28 October, 06:05
    0
    Apply logs to both sides

    logy=log10^x

    log y = x log10

    log y = x (1)

    x = log y / 1

    x = log y
  2. 28 October, 07:05
    0
    This equation isn't complete but if you are doing something that involves having y=10^whatever x is, then you just solve it like you would a normal equation, and then boom you have x and y.

    This equation isn't complete ...
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