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Jared Underwood
28 October, 05:51
How do you solve this If y=10^; then x=
+4
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Adolfo Mccann
28 October, 06:05
0
Apply logs to both sides
logy=log10^x
log y = x log10
log y = x (1)
x = log y / 1
x = log y
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Sherlyn Ross
28 October, 07:05
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This equation isn't complete but if you are doing something that involves having y=10^whatever x is, then you just solve it like you would a normal equation, and then boom you have x and y.
This equation isn't complete ...
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