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14 January, 04:54

A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t

seconds is given by the function h (t) = - 16t² + 32t + 6. What is the ball's maximum height? How long does it

take the ball to reach its maximum height? Round to the nearest hundredth, if necessary.

Reaches a maximum height of 22 feet after 1.00 second.

Reaches a maximum height of 22 feet after 2.00 seconds.

Reaches a maximum height of 44 feet after 2.17 seconds.

Reaches a maximum height of 11 feet after 2.17 seconds.

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Answers (2)
  1. 14 January, 06:12
    0
    Hello there.

    A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t

    seconds is given by the function h (t) = - 16t² + 32t + 6. What is the ball’s maximum height? How long does it

    take the ball to reach its maximum height? Round to the nearest hundredth, if necessary.

    Reaches a maximum height of 22 feet after 1.00 second.
  2. 14 January, 08:32
    0
    Differentiate the expression, to obtain expression for velocity. Set velocity to 0, this when max height is reached. Obtain the tmax from that expression.

    h (t) = - 16t² + 32t + 6

    h' (t) = - 32t² + 32

    0 = - 32t² + 32

    t max = 1

    hmax = - 16 (1) ² + 32 (1) + 6

    hmax = 22

    Therefore, first option is the correct answer.
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Home » Physics » A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t seconds is given by the function h (t) = - 16t² + 32t + 6.
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