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19 February, 02:46

A test charge is introduced into the electric field of a charge. It feels a force of 2F where the electric field is 2E. What would the force on the test charge be where the electric field is 8E?

Somebody explain how you would get the answer.

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  1. 19 February, 05:55
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    We know, q = F / E

    q = 2 / 4

    q = 1/2

    Now, we have: q = 1/2 and E = 1

    Substitute the value into the expression:

    F = E. q

    F = 1/2 * 1 = 1/2

    In short, Your Answer would be 1/2
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