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Paige Hurst
10 September, 19:07
Derivative of arcsin (cos (2x))
is this chain rule?
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Selina
10 September, 20:46
0
Yes, you need to use the chain rule. Also you need to use the derivative of arcsin which is in tables.
Derivative of y = arcsin (x) = 1 / [√ (1 - x^2) ]
Chain rule: Derivative of archsin (cos (2x)) =
y' = 1 / [√ (1 - (cos (2x)) ^2) ] * derivative (cos (2x) =
y' = 1 / [√ (1 - (cos (2x)) ^2) ] * ( - sin (2x)) * 2
y' = - 2 (sin (2x)) / [√ (1 - (cos (2x)) ^2]
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