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10 September, 19:07

Derivative of arcsin (cos (2x))

is this chain rule?

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  1. 10 September, 20:46
    0
    Yes, you need to use the chain rule. Also you need to use the derivative of arcsin which is in tables.

    Derivative of y = arcsin (x) = 1 / [√ (1 - x^2) ]

    Chain rule: Derivative of archsin (cos (2x)) =

    y' = 1 / [√ (1 - (cos (2x)) ^2) ] * derivative (cos (2x) =

    y' = 1 / [√ (1 - (cos (2x)) ^2) ] * ( - sin (2x)) * 2

    y' = - 2 (sin (2x)) / [√ (1 - (cos (2x)) ^2]
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