If a lamp has a resistance of 136 ohms when it operates at a power of 1.00 * ^2, what is the potential difference across the lamp?

Given resistance in ohms and current in ampere, the power can be calculated by the equation,

P = I² x R

where I is current, P is power, and R is resistance

Substituting the given values,

1.00 x 10² = (I²) x 136 ohms; I = 0.8575 amp

Then, by Ohm's law, the value of V = I x R. Substituting,

V = (0.8575 amp) x (136 ohms) = 116.619 volts

Thus, the potential difference across the lamp is approximately equal to 116.619 volts.