Ask Question
9 December, 12:45

In an experiment conducted using the Young's double-slit apparatus, the separation between the slits is 20 µm. A first-order constructive interference fringe appears at an angle of 2.5o from the zeroth order (central) fringe.

A. What wavelength of light is used in the experiment?

B. At what angle would the fourth-order (m = 4) bright fringe appear?

C. At what angle would the fourth-order (m=4) dark fringe appear?

+3
Answers (1)
  1. 9 December, 13:07
    0
    To solve this problem, we use the formula

    λ = s sin θ

    where s is the separation and θ is the angle interference

    So,

    λ = 20 x 10^-6 sin 2.5

    λ = 8.72 x 10^-7 m

    The required angle for the fourth order bright fringe is

    θb = sin⁻¹ (4λ / s) = sin⁻¹ (4 (8.72 x 10^-7 m) / 20 x 10^-6) = 10.04°

    The required angle for the fourth order dark fringe is

    θd = sin⁻¹ (4.5 λ / s) = sin⁻¹ (4.5 (8.72 x 10^-7 m) / 20 x 10^-6) = 11.31°
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In an experiment conducted using the Young's double-slit apparatus, the separation between the slits is 20 µm. A first-order constructive ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers