What happens to the current in a circuit if the resistance triples? If the voltage triples?

(Example 1)

If the Voltage that furnishes the current is an ideal (no internal resistance) Voltage source. Then;

V/R = i

V/2R = i/2 If external resistance doubles, current reduced to 1/2 of original value

V/3R = i/3 If external resistance triples, current reduced to 1/3 of original value

(Example 2)

But if the Voltage that furnishes the current is a practical [contains an internal resistance (Ri) ] Voltage source. Then the current is a function of the Voltage source's internal resistance, which does not double nor triple, plus the external resistance which is being doubled and tripled.

V / (R + Ri) = i

V / (2R + Ri) = greater than i/2 but less than I.

V / (3R + Ri) = greater than i/3 but less than i/2