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31 January, 17:32

A 565 N rightward force pulls a large box across the floor with a constant velocity of 0.75 m/s. If the coefficient of friction is 0.8, what is the weight of the box?

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  1. 31 January, 20:06
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    The first thing you should know is that the friction force is equal to the coefficient of friction due to normal force.

    Therefore, clearing the normal force we have:

    The friction is 565N.

    (565 / 0.8) = 706.25N. weight.
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