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13 September, 00:19

An ideal spring obeys hooke's law: f = - bikx. a mass of m = 0.3 kg hung vertically from this spring stretches the spring 0.13 m. the acceleration of gravity is 9.8 m/s 2. calculate the value of the force constant k for the spring. answer in units of n/m

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  1. 13 September, 04:13
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    The force = 0.3 * 9.8 = 2.94

    x = 0.13

    k = 2.94/0.13

    k = 22.6 N/m
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