A skater holds her arms outstretched as she spins at 130 rpm. what is the speed of her hands if they are 130 cm apart?

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Physics

Adams

20 July, 04:11

A skater holds her arms outstretched as she spins at 130 rpm. what is the speed of her hands if they are 130 cm apart?

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Dayanara Blankenship · Answer 1

This is about tangential vs angular velocity but it is not part of angular momentum which will be explained later on.

Her angular velocity w = 130 rpm = 2pi 130/60 radian/sec. The radius of rotation r = R/2 = 1.3/2 =.65 m from nose to hand.

Thus the tangential velocity of each hand is v = wr = 2pi*3/2*.65 = 6.1261 mps.

Angular momentum L = Iw; where:I = kmr^2 is the inertia and w is the angular velocity. k is a continuous contingent on the shape and density supply of the rotation mass m. So you can see, the problem has zero to do with angular momentum.