A pebble is dropped down a well and hits the water 1.5 seconds later. using the equations for motion with constant acceleration, determine the distance from the edge of the wall to the water's surface.

Let h = the distance from the edge of the wall to the water surface (m).

Use g = 9.8 m/s² and neglect air resistance.

The initial vertical velocity of the pebble is zero.

Because the pebble hits the surface of the water after 1.5 s, therefore

h = (1/2) * (9.8 m/s²) * (1.5 s) ² = 11.025 m

Answer: 11.025 m