If the cd rotates clockwise at 500 rpm (revolutions per minute) while the last song is playing, and then spins down to zero angular speed in 2.60 s with constant angular acceleration, what is α, the magnitude of the angular acceleration of the cd, as it spins to a stop? express your answer in radians per second squared

Question

Physics

Bernard Wallace

20 October, 15:19

If the cd rotates clockwise at 500 rpm (revolutions per minute) while the last song is playing, and then spins down to zero angular speed in 2.60 s with constant angular acceleration, what is α, the magnitude of the angular acceleration of the cd, as it spins to a stop? express your answer in radians per second squared

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Answers (1)

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Trevon Knight · Answer 1

The solution for this problem is:

500 revolution per minute = 8.33rev / s = 2π*8.33 rad / s = 52.36 rad / s

Angular velocity ω = 2π N

Angular acceleration α = (ω2 - ω1) / t

ω2 = 0

α = - ω1/t = - 2π N / t

N = 500 rpm = 8.33 r p s.

α = - 2π 8.33 / 2.6 = - 20 rad/s^2