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12 June, 19:57

What temperature, in ∘c, is a blackbody whose emission spectrum peaks at 250 nm?

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  1. 12 June, 20:57
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    Wein's law states that:

    Peak wavelength (m) * Temperature (K) = 2.898*10^-3 m. K

    In this case, Peak spectrum = 250 nm = 250*10^-9 m

    Temperature (K) = (2.898*10^-3) / (250*10^-9) = 11592 K

    In °C, Temperature = 11592-273.15 = 11,318.85 °C
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