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17 August, 15:06

A 0.10 kg ball of dough is thrown straight up into the air with an initial speed of 15 m/s.

a. find the momentum of the ball of dough at its maximum height.

b. find the momentum of the ball of dough halfway to its maximum height on the way up

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  1. 17 August, 16:44
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    Mass of the ball is m = 0.10kg Initial speed of the Ball v = 15m/s a. When the ball is at maximum height the velocity is 0 Momentum of ball = mass x velocity Momentum = 0.10kg x 0 = 0 b. Getting the maximum height, Using the conservation of energy equation KEinitial = mgh 1/2mVin^2 = mgh = > h = v^2/2g h = 15^2/2x9.8 = 11.48m = > Half Height h = 5.96m Applying the conservation of energy equation at halfway V^2 = 2gh V = square root of (2x9.8x5.96) = > V = square root of (116.816) So the velocity at the half way V = 10.81 m/s Momentum M = m x V = > M = 0.10 x 10.81 = > M = 1.081kg-m/s
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