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1 February, 20:23

50 J of work was performed in 20 seconds. how much power was used to do this task?

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  1. 1 February, 20:51
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    Power = (amount of work done) / (time to do the work).

    = (50 J) / (20 sec)

    = 2.5 joule/sec = 2.5 watts.
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