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3 August, 12:21

A baseball is thrown upward from a height of 2 meters with an intial velocity of 10 meters per second. determine its maximum height, using a (t) = - 9.8 meters per second as acceleration due to gravity.

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  1. 3 August, 12:43
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    The equation to be used for this would be as follows:

    h (x) = - 9.8x^2 + 10x + 2

    We need to find for the axis of symmetry for the time it takes to reach the maximum height and is expressed as:

    x = - b / (2a)

    x = - 10/2 (-9.8)

    x = 0.51 seconds is the time it takes to reach the max. height

    h (x) = - 9.8x^2 + 10x + 2

    h (x) = - 9.8x0.51^2 + 10x0.51 + 2

    h (x) = 4.55 m
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