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14 January, 08:23

An electron in a mercury atom changes from energy level b to a higher energy level when the

atom absorbs a single photon with an energy of 3.06 electronvolts.

Calculate the frequency of the photon. [Show all work, including the equation and substitution

with units.]

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Answers (1)
  1. 14 January, 09:58
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    E = hf, where E is the energy of the photon, h the planck's constant, and f the frequency of the photon. Hence f = E/h, f = 3.06 eV / (6.63 x 10^-34 m^2 kg/s),

    f = (1.6 x 10^-19 kg m^2/s^2) / (6.63 x 10^-34 m^2 kg/s) = 2.41 x 10^14 Hz
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