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29 January, 17:08

An engine has an energy input of 125 J, and 35 J of that energy is transformed into useful energy. What is the efficiency of the engine?

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  1. 29 January, 18:02
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    Efficiency = (useful output) / (input)

    Efficiency = (35 J) / (125 J) = 0.28 = 28%
  2. 29 January, 18:42
    0
    Efficiency is equal to 35 / 125 * 100 which is equal to 28%.

    Efficiency is the ratio of the useful work performed by a machine or in a process to the total energy that it consumed.

    So basically it is the useful output which in this case was 35 J divided by the total input given to the machine which was 125 J in this case multiplying by 100 to get the percentage.

    If we did not need the percentage then we could have simply not multiplied it by 100.
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