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28 February, 23:54

A ball is thrown straight up at 15m/s. How long does the ball take to reach apex? What is the ball's total time of flight? ... ?

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  1. 1 March, 03:16
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    We use one fundamental kinematic equation for this problem. It is expressed as:

    v^2 = v0^2 - 2gh

    For this case, v = 0 and v0 = 15

    h = v0^2 / 2g = 15 / 2 (9.8) = 0.77 m

    Then, we use the equation:

    h = (v0) t-g t^2 / 2

    0.77 = 15t - (9.8) t^2 / 2

    t = 0.05 s
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